{"id":163,"date":"2022-04-08T05:07:00","date_gmt":"2022-04-08T05:07:00","guid":{"rendered":"http:\/\/6thclass.deltapublications.in\/?page_id=163"},"modified":"2025-01-30T11:14:44","modified_gmt":"2025-01-30T11:14:44","slug":"j-4-subtract-integers","status":"publish","type":"page","link":"https:\/\/6thclass.deltapublications.in\/index.php\/j-4-subtract-integers\/","title":{"rendered":"J.4 Subtract integers"},"content":{"rendered":"\n

Subtract integers<\/strong><\/h2>\n\n\n\n

key notes:<\/p>\n\n\n\n

\u25b6\ufe0f Subtracting a negative is the same as adding a positive.<\/td><\/tr><\/tbody><\/table><\/figure>\n\n\n\n

Subtracting integers on a number line<\/h4>\n\n\n\n

You can use a number line to subtract integers, too.<\/p>\n\n\n\n

Subtracting a number is the same as adding its opposite. For example, 4\u20133 is the same as 4+(\u20133).<\/p>\n\n\n\n

So, you can rewrite a subtraction expression as an addition of the opposite. Then, follow the rules for adding integers.<\/p>\n\n\n\n

Subtracting a positive integer<\/h4>\n\n\n\n

Let’s try it. Subtract 3\u20137.<\/p>\n\n\n\n

First, rewrite the subtraction problem as the addition of the opposite. The opposite of 7 is \u20137.<\/p>\n\n\n\n

3\u20137=3+(\u20137)<\/p>\n\n\n\n

Then, use a number line to add. Find 3 on the number line. Since \u20137 is negative, move 7 units to the left.<\/p>\n\n\n\n

\"A<\/figure>\n\n\n\n

Since you land on \u20134, the answer is \u20134.<\/p>\n\n\n\n

So, 3\u20137=\u20134.<\/p>\n\n\n\n

Subtracting a negative integer<\/h4>\n\n\n\n

Let’s try another one. Subtract \u20132\u2013(\u20135).<\/p>\n\n\n\n

First, rewrite the subtraction problem as addition of the opposite. The opposite of \u20135 is 5.<\/p>\n\n\n\n

\u20132\u2013(\u20135)=\u20132+5<\/p>\n\n\n\n

Then, use a number line to add. Find \u20132 on the number line. Since 5 is positive, move 5 units to the right.<\/p>\n\n\n\n

\"A<\/figure>\n\n\n\n

Since you land on 3, the answer is 3.<\/p>\n\n\n\n

So, \u20132\u2013(\u20135)=3.<\/p>\n\n\n\n

Rules for subtracting integers<\/h4>\n\n\n\n

You can subtract integers without number lines. Rewrite the subtraction problem as addition of the opposite and follow the rules for adding integers.<\/p>\n\n\n\n

Subtracting a positive integer<\/h4>\n\n\n\n

Let’s try it. Subtract \u20132\u20133.<\/p>\n\n\n\n

First, rewrite the subtraction problem as addition of the opposite.<\/p>\n\n\n\n

\u20132\u20133=\u20132+(\u20133)<\/p>\n\n\n\n

Now, follow the rules for adding integers. The signs of the addends are the same, so add their absolute values.<\/p>\n\n\n\n

|\u20132|+|\u20133|=2+3=5<\/p>\n\n\n\n

Since both addends are negative, the sum is also negative. <\/p>\n\n\n\n

So, \u20132\u20133=\u20135.<\/p>\n\n\n\n

Subtracting a negative integer<\/h4>\n\n\n\n

Let’s try another one. Subtract \u20132\u2013(\u20133).<\/p>\n\n\n\n

First, rewrite the subtraction problem as addition of the opposite.<\/p>\n\n\n\n

2\u2013(\u20133)=\u20132+3<\/p>\n\n\n\n

Now, follow the rules for adding integers. The signs of the addends are different, so subtract the lesser absolute value from the greater absolute value.<\/p>\n\n\n\n

|3|\u2013|\u20132|=3\u20132=1<\/p>\n\n\n\n

Since the positive addend, 3, has a greater absolute value, the sum is positive.<\/p>\n\n\n\n

So, \u20132\u2013(\u20133)=1.<\/p>\n\n\n\n

Learn with an example<\/strong><\/p>\n\n\n\n

\n
\n

Subtract:<\/p>\n\n\n\n

-7 \u2212 10 =?<\/p>\n\n\n\n